(14)巧妙算盤的原本
一段的算盤
算珠往下,往上都是歸零,
每檔十珠,十檔百珠俄羅斯算盤,
歸零後就是11進位制算盤,
當你我面對面,我往前,你往後,
開始撥珠對打,所以任何算盤,
歸零後就是對打盤,
算盤代數式 11=10 +1
+1 就是 加上0 這個數碼,
因此任何算盤的代數式,
進位值 = 珠數 + 1
E = A + 1 一段盤
E是進位值,A是每檔珠數,
所以每檔珠數1個,
則 1 +1=2 ,是二進制算盤,
每檔珠數4個,
則 4 +1=5 ,是五進制算盤,
例如上一下四的日本算盤,
上段是二進制盤,下段是五進制盤,
∴ E = A +1 代數基本式
每檔珠數9個是十進數算盤,
∵10= 9 +1
二段算盤, A , B 即上,下段珠數,
E = (A+1) × (B+1)
10 = (1+1) × (4+1) 上一下四盤
18 = (2+1) × (5+1) 上二下五盤
算盤無段數上限,無檔數上限,
證明整數無限大,或無限小"負數",
歸零都是對打盤,證明0即開始,
得證自然數是整數的集合,
且珠值上,下珠都可當1計數,
充分必要驗證整數一個一數,
歸零法個數的指數律代數式
∵檔串珠,珠可上,可下,即底數為2,
一段盤是指數1
二段盤是指數2
三段盤是指數3,類推且無上限,,,
∴歸零法個數
一段盤 2的1次方 = 2 種
二段盤 2的2次方 = 4 種
三段盤 2的3次方 = 8 種
四段盤 2的4次方 = 16 種
類推且無上限,,,
算盤證明歸零是自然法則,
個人心得是"充分"且"非必要",
理由這個"充分"按"循環"而不止,,,
按類推無上限的循環可得證,
直推宇宙時光機同理而無止盡,,,,
(14) ingenious abacus of the original
An abacus
Count beads down, are up to zero,
Each file ten bead, ten file 100 beads Russian abacus,
After zero is 11 carry calculation plate,
When you and I face to face, I move forward, you back,
Began to beat the bead, so any abacus,
After zero is on the hit,
Abacus Algebra 11 = 10 +1
+1 is plus 0 this number,
So any aliens of the abacus,
Carry value = beads + 1
E = A + 1
E is the carry value, A is the number of stakes per stall,
So each file number 1,
Then 1 + 1 = 2,is a binary abacus,
4 stalls per stall,
Then4+1=5,is the pentad abacus,
For example, on the next four Japanese abacus,
The upper section is a binary disk, the lower section is a pentad disk,
∴ E = A +1 algebraic basic
The number of each file is 9 decimal count abacus,
∵ 10 = 9 +1
Two paragraph abacus, A, B is the upper and lower beads,
E = (A + 1) × (B + 1)
10 = (1 + 1) × (4 + 1) on the next four sets
18 = (2 + 1) x (5 + 1) on the next two
Abacus no limit, no limit number,
To prove that the integer infinite, or infinitely small "negative"
Zero is on the play, that 0 is the beginning,
The natural number is a set of integers,
And the value of the beads, the beads can be a count,
It is necessary to verify the integer one by one,
Exponential law algebraic number of zero number
∵ file beaded, beads can be on, but the next, that is, the bottom of 2,
A disk is an index of 1
The second segment is the index 2
Three sections of the index is 3, analog and no limit ,,,
∴ the number of zero
A disk 2 of the first power = 2 kinds
Second paragraph 2 of the 2 = 4
Three of the three discs = 8
Four of the four discs = 16 species
Analogy and no limit ,,,
Count to prove that zero is a natural law,
Personal experience is "full" and "unnecessary"
Reason for this "full" by "loop" and more than ,,,
By the type of no limit can be approved by the cycle,
Directly push the universe time machine with the same, and only ,,,,
