⑹ + - × ÷ 的原本
÷ 是 - 的速算法,與 × 相反互逆
÷ × 互為逆運算,如 + - 是逆運算
+ ⇄ -
↯ ↯
× ⇄ ÷
16 + □ = 33 , □ = 33 - 16 = 17
○ - 28 = 45 , ○ = 45 + 28 = 73
19 × ☆= 57 , ☆ = 57 ÷ 19 = 3
◇ ÷ 15 = 8 , ◇ = 8 × 15 = 120
除法是減法延伸,減法不適合交換
除法也不適合交換。加,乘則皆可
6+6+6=6×3 乘是加的速算
5+9=9+5 ∵加適合交換律
9×5=5×9 ∴乘也適合
10顆糖分二盤,每盤幾顆糖?
10 - ( ) - ( ) = 0
∵10 ÷ 2 = ( )
∴減法的速算是除法
65人分座五台車,每車幾人?
65 -□ -□ -□ -□ -□ = 0
65 = □ × 5 , □ = 65 ÷ 5 =13
⑹ + - × ÷ the original
÷ is - the speed algorithm, and × opposite the inverse
÷ × mutually inverse operation, such as + - is the inverse operation
+ ⇄ -
↯ ↯
× ⇄ ÷
16 + □ = 33, □ = 33 - 16 = 17
○ - 28 = 45, ○ = 45 + 28 = 73
19 × ☆ = 57, ☆ = 57 ÷ 19 = 3
◇ ÷ 15 = 8, ◇ = 8 × 15 = 120
Division is a subtraction extension, subtraction is not suitable for exchange
Division is not suitable for exchange. Plus, multiplication can be
6 + 6 + 6 = 6 × 3 multiplication is the speed of the operator
5 + 9 = 9 + 5 ∵ add the appropriate exchange law
9 × 5 = 5 × 9 ∴ multiplication is also suitable
10 candy two sets, each few sugar a few?
10 - () - () = 0
∵ 10 ÷ 2 = ()
∴ subtraction of the speed is divided
65 seats five cars, several people per car?
65 - □ - □ - □ - □ - □ = 0
65 = □ x 5, □ = 65 ÷ 5 = 13
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